The conversion of CH_3-CH_2-CHO to CH_3-CH_2- | vedclass

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Question

(C) The reaction involves the addition of a Grignard reagent to an aldehyde. $1$. $CH_3-CH_2-CHO + CH_3MgI \xrightarrow{H_3O^+} CH_3-CH_2-CH(OH)-CH_3$

Vedclass · Accepted Answer

$(i) CH_3MgI, H_3O^+; (ii) HBr$

Vedclass · Answer

(C) The reaction involves the addition of a Grignard reagent to an aldehyde. $1$. $CH_3-CH_2-CHO + CH_3MgI \xrightarrow{H_3O^+} CH_3-CH_2-CH(OH)-CH_3$. $2$. This reaction directly yields the secondary alcohol $CH_3-CH_2-CH(CH_3)-OH$ from propanal $(CH_3-CH_2-CHO)$ using methylmagnesium iodide $(CH_3MgI)$ followed by acidic hydrolysis $(H_3O^+)$. $3$. Therefore,the conversion is achieved in a single step using $CH_3MgI$ and $H_3O^+$.

The conversion of $CH_3-CH_2-CHO$ to $CH_3-CH_2-CH(CH_3)-OH$ is achieved by:

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